100

How can we calculate 100 using each digit 0 - 9 exactly once in order?


I don't know, but here are some of them.

0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 x 9

0 + (1 + 2 - 3 - 4)(5 - 6 - 7 - 8 - 9)

0 + 123 + 45 – 67 + 8 – 9

0 + 123 - 45 - 67 + 89

0 + 123 + 45 - 67 + 8 - 9

0 + (((1 * 2) + 3) * 4 * 5) + 6 – 7 – 8 + 9

0 + ((((1 / 2) * 3) / 4) * 56) + 7 + (8 * 9)


And here are some in reverse order.

98 - 76 + 54 + 3 + 21 + 0

98 + ( 76 - 54 ) / ( 3 - 2 + 1 + 0 )

98 + ( 7 - 6 ) + 54321 ^ 0

98 + 7 - 6 + 5 - 4 + 321 * 0